Open in TheBrain

13 - The complex exponential function

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welcome to the third lecture in our

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third week of the grist analysis of a

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complex kind today we'll learn about the

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complex exponential function you started

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talking about this function at the end

00:12

of last class we discovered that the

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function f of Z defined by e to the x

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times cosine y plus I times e to the X

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sine Y it's an entire function whereas e

00:26

is X plus iy and e to the X cosine Y and

00:30

sine Y are just the regular real valued

00:33

functions that we know from calculus

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let's look at some of the properties of

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this function suppose for example that Y

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is equal to 0 so this Y right here is

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equal to 0 while cosine of 0 is equal to

00:49

1 and so this Y would also be equal to 0

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but sine of 0 is equal to 0 so in that

00:56

case this function would simplify the e

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to the x times 1 plus I eetu the x times

01:05

0 but that's just either X because this

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whole last term gets cancelled out by

01:12

the 0 so when 1 is equal to 0 then f of

01:15

Z is simply Eve X in other words the

01:19

function f agrees with our regular

01:22

exponential function if you plug in

01:24

something real it doesn't have an

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imaginary part another thing to notice

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is that we could rewrite f of Z a little

01:32

bit we can factor out the e to the X

01:35

term right here and are left with e to

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the x times parentheses cosine y plus I

01:42

sine Y but cosine y plus I sine Y we

01:46

found an abbreviation for we call that e

01:48

to the I Y even though we weren't quite

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sure why we called it either the iy was

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an abbreviation at the time but now that

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we're looking at e to the x times e to

01:59

the I Y we would like to think of this

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as e to the X plus iy because there

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rules for our regular real valued

02:08

exponential function would indeed

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is to combine these two exponents we

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have improved any such thing right now

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but this is a reasonable thought to have

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and that looks like e to the Z whatever

02:20

e to the Z might be so with these

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thoughts in mind we actually define the

02:26

complex exponential function e to the G

02:29

exactly like that it's also sometimes to

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notice X plus Z and it's defined by even

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the Z is e to the x times e to the I by

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where Z is X plus iy and even the iy is

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still shorthand for cosine y plus I sine

02:44

1 this is the complex exponential

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function and we'll explored in today's

02:50

lecture again as a reminder a to the Z

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is e to the x times e to the iy what

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does step length of a the Z so how far

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is e to the Z from the origin or the

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absolute value of e to the Z can be

03:03

found by simply taking the absolute

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value of e to the x times e to the iy

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and we know the absolute value of the

03:10

product of two complex numbers is the

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product of the absolute values norm of X

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norm of the iLife but e to the iy

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remember what that really is e to the I

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Y short for cosine y plus I sine Y and

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it is simply a number on the circle of

03:29

radius one such that the angle formed

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with a positive real axis is y this is e

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to the I Y which was cosine y plus I

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sine Y all numbers of this form have

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distance 1 from the origin because

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they're on the circle of radius 1 so the

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number of e to the I Y is 1 just by how

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this number even though I wise to find

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the norm of e to the X e to the X is our

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real valued exponential function

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remember what that looks like

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e to the X looks like this this is the

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regular exponential function it's always

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above the x-axis it's always positive it

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can never be negative so the norm of e

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to the X is simply e to the X what's the

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argument of Eden is e now that we know

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how far each of the Z is from the origin

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we would like to know

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what angle is a form with a positive

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real axis what's the argument of e to

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the x times e to the I wha what is e to

04:30

the x times e to the I Y that's a number

04:32

in polar form where this is its length

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or radius but for a number in polar form

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radius times either I something be

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something gives to the angle let it

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forms with a positive real axis so the

04:45

angle this number form so the positive

04:47

real axis is y truthfully speaking I

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should have written me a plus 2 pi K

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where K is any integer so the way you

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should read this equations and argument

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of e to the Z is y what is e to the Z

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plus 2 pi I so suppose you add 2 pi I to

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you Z and then stick that into the

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exponential function while since 2 by is

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peel the imaginary that means you're

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really adding that to the imaginary part

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of Z so it's the same as e to the x

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times e to the I y plus 2 pi adding the

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2 pi to the imaginary part of Z but e to

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the I theta is a function that is

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periodic with period 2 pi because we're

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looking at the angle let us form to the

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positive real axis and it starts

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repeating after 2 pi so e to the I y

05:41

plus 2/5 it's the same as e to the I wat

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so that this simplifies to the e the x

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times e to the iy which is it Lizzie so

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the function e to the Z is periodic and

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the period is

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to heii you add 2 pi i to Z the

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exponential function remains the same

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finally we would like to establish some

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properties that are similar to the ones

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that we have for the real valued

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exponential function we would hope that

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e to the Z plus W is e to the Z times e

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to the W let's check that this Holtz

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with our definition of e to the Z which

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is up here what is e to the Z plus W

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we'll write Z as X plus iy and W as u

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plus IV and plug that in so e to the Z

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plus W becomes e to the X plus iy plus u

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plus IV let's reorganize and collect the

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real parts and collect the imaginary

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parts because we'll need those to apply

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the definition of our exponential

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function the real part of the sum and

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the exponent is X plus U and the

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imaginary part is y plus V now we know e

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to this complex number is e to the real

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part so e to the X plus u times e to the

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I times the imaginary part so e to the I

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times y plus V that's just by definition

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of the exponential function e to the X

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plus u now we're talking all real values

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XS real use real and E's our regular

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real valued exponential function so the

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rules of why this is even the x70 of the

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you either the iy plus V we proved that

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that equals e to the iy times e to the I

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V we use the addition theorems for sine

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and cosine functions and now we just

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reorganize things again we collect e to

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the X and e to the I 1 and then e to the

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U and E to the IV since it's a product

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of complex numbers and multiplication is

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commutative we can just reorganize

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things but even the x times e to the I Y

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that's simply e to the Z and if the you

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either the IV is e to the W and we

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established indeed that the same rule

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holds for complex values as it does for

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real guys what is 1 over e to the Z Y

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climb is e to the negative Z in the

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business that when they look at e to the

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Z times even a negative see by the rule

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we just established we can simply add

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the two exponents so that's either that

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Z plus negative Cecil Z minus Z but Z

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minus Z is 0 and e to the 0 is 1 so e to

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the Z times e to the minus e is 1 now if

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we divide both sides of this equation by

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e to the Z you find that either the

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minus Z is 1 over e to the C either the

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Z is an entire function we already

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showed this that's what set us off move

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define this function what's the

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derivative an entire function has a

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derivative remember that the way the

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function e to the Z is find its real

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part is e to the X s cosine Y and its

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imaginary part is e to the x times sine

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Y again we can find these partial

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derivatives that we learned about during

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the last lecture the partial derivative

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of U with respect to X means we

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differentiate e to the X cosine Y with

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respect to X keeping in mind that Y is

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fixed in a constant the derivative of e

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to the X e to the X cosine Y is a

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constant so UX is e to the X cosine Y

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similarly V X is e to the X sine 1 uy we

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now keep X constants or e to the X is a

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constant we need to find the derivative

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of cosine wise which is minus sine Y and

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V Y is e to the X cosine Y we learned

09:55

that for a function that's analytic its

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derivative can be found by taking UX

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plus IV X so therefore the derivative of

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our exponential function is e to the X

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cosine Y which is UX plus I times e to

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the X sine Y that's the VX

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but that's e to the Z in other words the

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derivative of e to the Z is e to the Z

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again or in singles DBC of e to the Z is

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e to the Z notice that we're using not

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the partial derivative symbols which

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were GDX we found we use that notation

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for the partial derivatives this is the

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complex derivative we use the way Euler

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d for that notation so similarly to the

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real-valued exponential function the

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derivative of the exponential function

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is the exponential function itself

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similarly the derivative of e to the

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constant times e how do you find that

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this is actually the composition of two

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functions the exponential function

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composed with a function that multiplies

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Z by a in other words we need to find

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the derivative of the outside function

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times the derivative of the inside

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function the inside function is a time Z

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its derivative is simply 8 therefore we

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get a times either the AC by the chain

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rule for the derivative of e of the AC

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what is e to the complex conjugate of C

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the complex conjugate of Z is X minus I

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Y Z was X plus iy therefore e to the Z

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conjugate equals e to the X is e to the

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minus I Y but we showed earlier and we

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can remember this in the picture what is

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e to the minus iy even the minus iy

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means for taking a negative angle minus

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y and get a number down here if we

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reflected that with respect to the x

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axis we would get this number up here so

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this is e to the minus I Y and this is

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either the iy in their complex

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conjugates of each other as this picture

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shows in other words even the minus iy

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is the conjugate of e to the iy e to the

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IX is real value we might just as well

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put a conjugate on top of it it makes no

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difference because real number equals

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its complex conjugate so we can extend

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the conjugation over the entire product

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but that's your conjugate of a Divisie

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in other words e to the conjugate of C

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equals the conjugate of e to the c1 is e

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to the Z equal to 1 well we need either

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the x times e to the iy to be 1 this is

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a number in polar form when it's a

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number in polar form equal to 1

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well it's length needs to be 1 it's

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angling to be 0 or 2 pi or 4 pi so in

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other words we need either the X to

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equal 1

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and we need Y to be zero or 2pi or 4pi

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when it's either the x equal to one

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that's the case when X is equal to zero

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so we need X is zero and Y of the form

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two K pi in other words we need Z to be

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of the form X plus iy so zero plus I

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times two K pi so those are the points

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where the exponential function takes the

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value 1 1 is e to the Z equal to e to

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the W we already saw that if Z is equal

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to W plus 2 pi I then e to the Z equals

13:56

e to the W but are there other

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possibilities for e to the Z to equal e

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to the W let's find out if we divide

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both sides of this equation by e to the

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W we know that 1 over e to the W is e to

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the minus W so either the Z divided by

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either the W becomes e to the Z minus W

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and that then needs to be equal to e to

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the W over e to the W which is 1 when

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this e to the Z minus W equal to 1 well

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that is the case when Z minus W is of

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the form 2 pi K in other words when Z is

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equal to W plus a multiple of 2 pi I so

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the cases we observed earlier were the

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only ways for e to the Z to equal e to

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the W let's understand that mapping w

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equals e to the Z we did this earlier

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for some other functions we look at it

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as a mapping from the Z plane to the W

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plane with W being equal to e to the C

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for example let's look at images of

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horizontal lines what's a horizontal

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line a horizontal line is of the form X

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plus iy 0 where y 0 is fix we're fixing

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the imaginary part and just varying X

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those points X plus iy 0 or they get

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mapped to e to the X plus iy 0 which is

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e to the X e to the iy 0 but Y zero is a

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fixed number so this is not going to

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change this is fixed and the only thing

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that can change is e to the X and e of X

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if X runs from negative infinity to

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infinity either the X will go from 0 to

15:43

infinity it will never take the value 0

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but anything as close to zero as

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possible and even though iy is a fixed

15:52

angle from the origin let's look at some

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examples for example this red dotted

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line right there

15:59

what is its image it's the line where y

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0 is equal to PI what is e to the I pi e

16:12

to the I pi is equal to negative month

16:16

performing an angle of Pi with a

16:20

positive real axis in other words all

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these numbers either the x times e to

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the i y0 lie on the negative real axis

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so the image of the red dotted line

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right here is the negative real axis

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accepting the origin

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let's look at the green line next what

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is its image in my picture it looks like

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the imaginary part is a little bit

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bigger than PI over two this angle here

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is just a little bit bigger than PI over

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2 e to the iy 0 is a point on the unit

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circle whose radius forms the angle y 0

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with a positive real axis and therefore

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the image of the green line is this

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green line right here let's look at the

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turquoise line

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it looks like it's imaginary part is

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around PI over 4 so the image is going

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to be this turquoise line right there

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how about the yellow line the yellow

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line up here has an imaginary part just

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a little bit bigger than pi so looking

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at this angle right here and therefore

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the image of the yellow line is this

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radial segment down here you notice that

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I drew another yellow line in the Z

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plane a little bit above minus I PI and

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indeed this reflects that the

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exponential function is periodic with

18:09

period 2 pi I this second be on a line

18:13

has distance 2 pi I from the other

18:15

yellow line in other words it's image is

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the same as the image of the other

18:19

yellow line so these two yellow lines

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both get mapped to the radio segment

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over in the W plane finally there's a

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purple line here and you can check that

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it gets them up to something like this

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purple line over here what are the

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images of vertical lines a vertical line

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is of the form X 0 plus iy where now X 0

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is fixed so the real part is fixed in

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the imaginary part varies those points

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get mapped to either X 0 plus iy which

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is feed the X 0 times e to the I 1 so

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now this number is fixed the distance

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from the origin is fixed for all these

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images and the angle varies in other

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words for a fixed line that's vertical

19:12

its image is a circle for example the

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yellow line that is on the imaginary

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axis so X 0 will be 0 it's mapped to

19:24

either 0 just 1 times either that I want

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but e to the I Y if Y is allowed to vary

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from negative infinity to infinity gets

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mapped to the circle and the circle is

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mapped over and over and over

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again because this keeps repeating

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there's zero here and say 2pi is right

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here then this little short segment

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already gets mapped to the full unit

19:49

circle and afterwards we just keep

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repeating

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similarly the red dotted line gets

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mapped to e to the x 0 times e bi y this

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x0 is a little bigger than 0 so either

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the x0 is bigger than 1 so it gets

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mapped to a circle whose radius is

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bigger than the previous one and if we

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move over to the green line its radius

20:14

it's going to be even bigger than the

20:17

one of the red circle similarly if I go

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to negative x zeroes e to the something

20:23

negative is going to be a number less

20:25

than what it's so positive but a number

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less than 1 so these radii are going to

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be less than 1 and the circles are going

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to be sitting inside the unit circle

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putting it all together we can actually

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figure out what the image of a vertical

20:43

strip is suppose we look at the set of

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all Z whose real part is between zero

20:47

and one so here's one and there's zero

20:51

and this is my vertical strip s what is

20:53

its image we already saw that the yellow

20:57

line which is on the imaginary axis gets

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mapped to the unit circle the green line

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for which I said the real part is equal

21:05

to 1 gets mapped to the circle of radius

21:08

II in other words the strip from 0 to 1

21:14

gets mapped to this annulus between the

21:18

circles of radius 1 and of radius II if

21:23

I draw a horizontal line this picture in

21:26

addition the one that I drew is maybe at

21:28

PI over 4 then I cut out a portion of

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that annulus so for example this

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turquoise portion here of the strip it's

21:40

mapped to this turquoise portion of the

21:42

annulus these kinds of pictures help you

21:47

understand what the exponential function

21:50

does graphically there's a few final

21:54

questions when is e to the Z equal to 0

21:58

well find out e to the Z is equal to 0

22:02

when e to the x times e to the iy is

22:04

here we know e to the I Y those are all

22:07

numbers on the circle of radius 1 they

22:10

can never be 0 when is a product of two

22:12

numbers 0 well one of the factors has to

22:14

be 0 the second one can't be 0 so it has

22:16

to be the first one so we need to either

22:18

bags to be 0 remember what even the X

22:20

looks like either the X looks like this

22:23

it never crosses the x axis it's never

22:27

equal to 0 in other words either the Z

22:30

can never take the value 0 just like the

22:34

real valued exponential function it

22:35

never takes the value 0

22:43

let's go a little bit further suppose

22:46

I'm giving you a point in the complex

22:48

plane not the origin but any other point

22:50

then cannot find a W such that e to the

22:54

W is equal to that point Z let's write Z

22:58

in polar form as absolute value of Z

23:01

tendency to beg theta and that's right W

23:04

in Cartesian form because that works

23:07

best for this problem so that's right W

23:10

is U plus IV then e to the W being e to

23:14

the Z is the same as e to the U times e

23:17

to the IV which is feed of the W being

23:20

equal to absolute value of Z that I say

23:23

that which is simply Z and this was e to

23:28

the W but these had two numbers in polar

23:33

form when are two complex numbers in

23:35

polar form the same well they would have

23:38

to agree in their distance from the

23:40

origin so even if you would have to be

23:42

the absolute value of Z and then their

23:44

angles have to agree modulo 2 pi e to

23:46

the IV would have to be eaten by theta

23:48

in other words when is e to the u equal

23:53

to the absolute value of Z this is all

23:55

via values now that's the case when use

23:57

a natural logarithm of the absolute

23:59

value of Z I'm going to e to the IV the

24:02

same as e to the I theta well being

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theta can only differ by a multiple of 2

24:08

pi

24:08

in other words w2c plus IB has to be of

24:14

the form natural log of Z that's my U

24:16

plus I times an argument of Z which is

24:20

what theta is you just saw the basic

24:25

ideas and how to define a complex

24:27

logarithm you see there's an issue

24:29

already with the argument being here the

24:32

argument function is a multivalued

24:34

function and we'd have to decide how to

24:36

pick the argument so that we could

24:37

hopefully make the logarithm function an

24:39

analytic function and indeed that as

24:41

possible

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