More arithmetic with negative msets
3,312 views Mar 14, 2023 Math Foundations
Let's illustrate this new box arithmetic using anti msets to define negative numbers, with some more explicit examples. This involves using integers not just for coefficients of polynomumbers / polynumbers, but also to crucially extend the possibilities for exponents to negative numbers. This introduces a vital symmetry into the world of algebra with polynumbers that is almost entirely missing from usual algebra courses: where essentially Laurent polynomials appear not in a calculus / analysis context, but as pure objects of analysis. This will have major consequences for our understanding of algebra going forward. A big thank you to all my Patreons supporters and Members of the Wild Egg mathematics courses channel. Video Contents:
More Arithmetic with negative msets
Anti-objects Negative mset
Examples of integer arithmetic
Examples of integer polynumber arithmeti
Multiplicative arithmetic with integer polynumbers
Integral (Laurent) polynumber
Arithmetic with integral polynumbers
More Arithmetic with negative msets
0:00
foreign [Music] I'm Norman Wildberger and I'm going to be extending this novel arithmetic of ours based
0:15
on multi-sets what we might call box arithmetic in the direction of negative numbers which we
0:23
got at by introducing anti-m sets a rather novel arithmetical feature that's somehow mysteriously
0:31
parallels the world of modern 20th century particle physics with the particle anti-particle
0:38
duality or symmetry that seems to pervade the physical World perhaps something parallel to
0:44
that actually sits at the heart of mathematics as well even though it hasn't really been explored
0:51
very much So today we're going to have a closer look at all this interesting arithmetic with some
0:57
examples okay so let me just remind you that the setup is that we're starting now with our zero
1:02
World consisting of two objects not a single zero which is the empty amp set but also the
1:08
anti-zero denoted with the same notation but with a superscript a and I'm also going to introduce
1:15
some possible variants that we could use in some situations one being just to replace the
1:20
black bounding brackets with red bounding brackets parallel to what an accountant would do in terms
1:29
of black and red representing you know positive and negative assets liabilities and perhaps when
1:38
we're using um sort of a typed situation with just on a line we could also perhaps introduce
1:45
perhaps braces just a suggestion to give us an alternate way of representing anti-am sets
1:53
Okay then we had these two very identical tables for the addition and multiplication
2:00
zero plus zero zero zero plus anti-zero is anti-zero same thing here and add to
2:06
zero plus anti-zero is zero and exactly the same actually for the multiplication
2:11
and curiously especially here this gives us this unusual law that zero times anti-zero is anti-zero
2:18
rather than zero which contradicts our experience that zero times anything is always zero so this
2:26
makes us a little bit uneasy this is certainly a different kind of arithmetic than we're used to
2:32
and as some viewers point out this also can be leading to a failure of the distributive law
2:39
at this very Elementary level with just zeros and anti-zeros so for example if we look at zero plus
2:46
zero times anti-zero Well zero plus zero is zero so that's going to be exactly this we're going to get anti-zero but on the other hand if we look at zero times anti-0 plus zero times anti-zero this
2:58
one's an anti-zero this one's an anti-zero and according to this the sum is then going to be zero
3:03
so the usual distributive law just at the level of these zero objects is not going to be valid
3:11
now that does not mean that the actual arithmetic that we're primarily interested in having to do
3:17
with numbers and poly numbers and multi numbers Etc is also necessarily inconsistent but it just
3:23
means that we do have to be rather careful about about questions of The Logical structure of things
3:29
and ultimately we want proofs and perhaps models of this that will ensure that what we're doing
3:36
is is logically consistent at this stage here it's exploratory and in that Spirit we're going to give
3:42
you some examples today of these these anti-m sets that are built up from this anti-zero and
3:49
also then negative numbers and then intervals integral poly numbers and integer polynumbers
3:56
extending the the negativity into the world of poly numbers so in some sense this is like a an
4:04
Assembly Language approach to arithmetic you know we're we're going really right down to a sort of a
4:10
fundamental level here and uncovering structure that's a little bit unfamiliar even though it
4:15
does lead to pretty familiar arithmetic but we get to look at that arithmetic in a new light
4:23
okay so last time we saw that as a consequence of having anti-zero we should probably extend
Anti-objects!
4:30
this anti-notion to msets very generally so that for any mset or object M in this arithmetic this
4:38
is going to be an anti-object which we denote by m super a okay which has the property that
4:45
if M and anti-m are together in an mset then they cancel out just like an electron and a positron
4:52
and we just get an empty mset as a result and we also saw that this m a this anti-m can be
5:02
evaluated by essentially adding the anti-0 to m in either order and in particular this shows
5:09
that the ante of anti-0 is is zero and extending that sort of black red approach to notation let me
5:20
suggest that we could use the following sort of two-dimensional version of that so if here's an
5:28
amp set M okay it's a box with a couple of boxes in it this is an empty box this box here has uh
5:35
two empty boxes in it okay so this would be what we would usually call this would be like one plus
5:46
Alpha squared in polynumber language if we wrote it out in terms of you know linear
5:52
structure there's a big mset with an empty M set there and here's an M set with head with two M sets inside it so if we were looking at this mset and trying to understand its anti-object so
6:03
M super a then I propose that we could denote that with a red bounding box so we take this
6:11
thing here and we we copy it essentially with the distinction that the outside box the containing
6:17
box is now red instead of black but the interior things are just the same as they were over here
6:24
and in the linear case that would involve replacing these outside brackets with red
6:31
brackets instead of black brackets but crucially what's inside stays the same now if we didn't have colors at our disposal okay then we could replace these red brackets with say
6:42
braces or whatever else we wanted to use I I like this two-dimensional uh representation because our
6:49
minds are very much oriented to two-dimensional visualization and understanding and so this makes
6:56
uh demonstrating things a little bit easier for us if we have too complicated something
7:01
like this it's fine for an AI or a computer but our physiology prefers to see things in this form
7:09
here so this is actually quite a useful way of illustrating some things okay so the first use
Negative msets
7:16
of these anti-objects is to Define minus one or I like to write one bar so one bar or minus one is
7:25
the mset consisting of a single anti-zero and it has the property then that if you add one bar with
7:32
one then you're going to get a zero or the empty set and then the multiplication of one and one bar
7:40
follows this sort of familiar pattern and then we can extend this negation to natural numbers
7:48
so if N is a natural number then we can Define n bar or minus n to be one bar times n and that
7:54
then introduces an extension of our fundamental objects from natural numbers to integers so so
8:01
we create integers by multiplying natural numbers by minus one so now we have a wider framework and
8:09
it's really this wider framework that is a very pleasant environment with lots of interesting
8:16
applications and furthermore if we have a more General mset a pure mset M then we can Define
8:24
its negative also M bar or minus M exactly in the same way we just multiply by one bar
8:32
so I remind you that in this world we can always add and we can always multiply M sets Okay it's
8:38
there's no requirement that these things necessarily be numbers those are just the top level things that there's a whole range of different more complicated kinds of objects and
8:48
these operations extend to all of them and then we also saw that another way of thinking about this M Bar was that it consists of the mset whose elements are the antes of all the elements of
9:00
capital M so it's the mset of m a as M ranges through capital M so let's do some examples of
Examples of integer arithmetic
9:10
some simple integer arithmetic two plus one bar plus four bar well two is the m side consisting
9:18
of zero zero one bar is the m set consisting of just the single anti-zero and four bar is
9:25
anti zero anti-zero anti-zero anti-zero when we add them we just dump everything out into
9:32
a single M set so we get zero zero anti-zero here and then a bunch of anti-zeros further
9:41
and then once we have them all in an M set then the zeros and the anti-zeros will mutually
9:47
annihilate each other okay so say that pair will disappear and that pair will disappear and we're
9:53
left just with anti-zero anti-zero anti-zero which we recognize as three bar or minus three
10:03
good okay what about three times two bar well three is a zero zero zero and two bar is anti-zero
10:14
anti-zero how do we multiply these well we have to form the Big M set consisting of all possible
10:21
sums of elements here with elements here so we have to be able to evaluate zero plus anti zero
10:28
which we know is anti-zero and there's going to be six possible such things so we're going to get
10:37
that thing which we recognize as six bar okay let's illustrate uh the sort of the fact that multiplication and in fact addition also
10:48
are not essentially binary operations in this world they're in principle uh things that can
10:55
input a whole bunch of things at the same time so let's multiply two Bar times four bar times
11:00
one bar so that's anti-zero anti-zero there's two bar multiplied by anti-zero
11:08
anti-zero anti-zero anti-zero there's four bar multiplied by just anti-zero that's one bar
11:15
so what are we gonna have to do we're going to have to take a multi-set which consists of all
11:23
possible sums of elements here F elements here with elements here okay so I'm going to take one
11:29
of these anti-zeros one of these anti-zeros and one of these anti-zeros we're going to add them
11:35
so over here is on the side let's just compute this thing anti-zero plus anti-zero plus anti-zero
11:47
well anti-0 plus anti-0 is zero and zero plus anti zero is anti-zero so this just gives us
12:02
anti-zero in fact more generally if we had K anti-zeros all added together
12:11
then whether we get zero or anti-0 as the final result depends on whether K is even
12:16
or odd if there's an odd number of anti-zeros we're going to get an anti-zero if there's an even number of anti-zeros we're going to get a zero and because the addition and the
12:26
multiplication tables are the same that's the same statement if we replace the additions here with multiplications so anti-zero times anti-zero times anti-zero is also going to be anti-zero
12:36
okay so it's clear what we're going to get here we are going to get a whole bunch of anti-zeros
12:44
a whole bunch of them one two three four five six seven eight and so the final result is eight bar
12:54
okay so now we can convince ourselves that the arithmetic that we've cooked up here really does obey the same rules as our usual integer arithmetic with respect to the operations addition
13:05
and multiplication okay so let's go down one level to the poly numbers so I remind you that a poly
Examples of integer polynumber arithmetic
13:14
number is an mset of natural numbers so let's look at an example here's an mset of natural numbers p
13:21
is the mc00225 these are all natural numbers and this has an interpretation in terms of sort of
13:28
more usual notation as 2 plus 3 Alpha squared plus Alpha to the five and if we connect with
13:39
the my usual preferred notation for poly numbers like we use in the algebraic calculus course or
13:45
that we've talked about extensively in the Math Foundation series we can think of a poly number
13:51
it's like a polynomial as a list a vertical lists say typically of coefficients the actual variable
13:58
itself is sort of secondary it's sort of implicit it's really the coefficients that are the crucial thing so here there's a two there's zero Alphas three Alpha squares zero Alpha Cube zero Alpha
14:09
to the fourth one alpha to the fifth so let me just point out again the important distinction
14:16
here between this more classical approach to what a poly number is namely as a list okay
14:23
um and this this other this new point of view this mset point of view towards what a poly number is
14:29
okay so these are closely connected in the sense that this thing here is really the multiplicity
14:34
list for this m set this is keeping track of how many of each of these objects we have because
14:41
the objects appearing here are naturally ordered they're natural numbers so 0 1 2 3 Etc so we can encode this information just sort of by counting how many zeros there
14:52
are how many ones there are how many twos there are how many threes there are Etc
14:58
but there's a sense in which this is actually a more basic or fundamental
15:04
object okay because the ambiguity that's appearing over here that you're allowed
15:10
to add additional zeros below wherever you are and doesn't change that is sort of removed at
15:18
the multi-set level because we don't have to say that we're just talking about a multi-set
15:23
so this is a a subtle but important shift that I do want you to take on board that
15:29
perhaps a poly number is really sort of more fundamentally on mset of natural numbers
15:36
okay so now we want to enlarge that view because now we have integers okay we have integers so
15:44
let's see what happens if we extend this notion to involve integers so here's the negation of this p
15:53
okay how do we negate an amp set of P bar or minus B well we just take the anti of each one of these
16:01
so we have zero anti or anti-zero anti-zero anti-2 anti-2 anti-2 anti-five and that's also
16:11
a poly number A Familiar kind of poly number but one involving negative coefficients so
16:18
if we wrote it out in as a as a poly number in Alpha it'd be two bar plus
16:25
three bar Alpha squared so there's really three um Alpha squares here but there's there's antes here
16:32
so it's representing three bar Alpha squared and one bar Alpha to the five and as a vertical list
16:40
we could write a minus two zero minus three zero zero minus one or I prefer 2 bar 0 3 bar 0 0 1 bar
16:48
notice also that I'm putting the one bar here okay we're sort of forced to here because we
16:53
don't have a subtraction operation so it would be wrong for us to say minus Alpha the five not
16:59
wrong but not really consistent with what we're doing so far so far we really only have addition and multiplication so strictly speaking to be consistent we probably also should put a 1 here
17:09
okay it's probably a little bit more consistent if we treat all these things sort of uniformly
17:15
and you know treat the ones uh same as the twos and the threes I suppose we could even
17:23
go one step further and write zeros zero Alpha et cetera but that would that's maybe going a bit too far but anyway so this is the negation of of this thing here in sort of an obvious way
17:36
but so we're also allowed to mix and match these things so if we can have a situation where we have a poly number which has both positive and negative coefficients for example this Q thing here have a
17:46
look at it it's uh M said 0 1 a or anti one two a and three so as a poly number this would be well
17:58
there's a single one um uh there's one there's a one to the a here so that's like uh one bar
18:08
times Alpha and there's a one bar times uh Alpha squared and there's a one bar times Alpha cubed
18:21
so what would happen if we added say p and Q well we have to put them all together in a Big
18:30
M set okay so um there's a zero here a zero here and a zero so it'll be three zeros there's a one
18:37
a there's a two two two we'll put two two two in and we also have to put a 2 a in an anti-2
18:44
but that 2A is going to cancel with one of the twos okay so they're going to go so we're just
18:50
gonna have two two and then we'll get a three and also a five so the result would be three plus one
18:57
bar Alpha plus two alpha squared plus one alpha cubed if we wanted to plus one alpha to the five
19:06
and you know more colloquially we would write this or say it as 3 minus Alpha plus two alpha squared
19:13
plus Alpha cubed plus Alpha Phi that would be the more familiar uh sort of high school way of saying
19:19
it but that does assume that we have a subtraction operation which we're not assuming at this point
19:24
okay so that's the way anti numbers generate negative coefficients so it's the antes inside
19:32
the brackets that are generating negatives sort of outside the brackets maybe that's
19:37
one way of thinking about it great so let's do a little bit of multiplicative arithmetic
Multiplicative arithmetic with integer polynumbers
19:43
with these integer polynumbers say 2 plus Alpha times 3 minus Alpha squared first of
19:52
all let's over here just draw a picture of this thing here okay so what is 2 plus Alpha
19:57
so it's a box that has what in it well it's going to have two empty M sets so we just had that that
20:05
would be the number two okay but it also has an alpha in it what's an alpha well an alpha is
20:13
when you put a 1 inside this box here so 2 plus Alpha looks like this
20:22
and now we're multiplying it by 3 minus Alpha squared what does that look like well that's also a box okay and it has a 3 in it okay okay so it's the three zeros in there that
20:35
makes the three and then there's a minus Alpha squared so what does that look like well an alpha
20:42
squared would be like when you had um a box here with two empty boxes inside okay but we have a
20:52
minus Alpha squared so I actually need to change colors and introduce a red box because we have
21:01
um we have a minus Alpha squared so I'm going to put a box here and a box here have a look at this
21:12
okay so if we didn't have this thing here okay if we remove those three things and just looked at this big black box with a red box inside it and two black marks this would
21:22
be the negation of the the thing that we got by replacing this red box with a black
21:30
box okay if we replace the red box with a black box then we would have Alpha squared
21:36
all right so negative Alpha squared you get that by by taking this thing here and and changing the
21:42
color of all the ingredients in other words replacing all the ingredients with antes so
21:47
the minus Alpha squared is represented by this big box with a red box inside it containing two black boxes okay so you know we could do the arithmetic at the Box level
21:59
but uh so let's let's uh sort of do it in a more regular fashion so 2 plus Alpha
22:07
so um what's this going to look like so this is going to be uh an amp set it's a poly number so
22:12
it's an M set of natural numbers or these days integers so 2 is representative zero zero and the
22:20
alpha is represented by the one okay and we have to multiply it here's another M set consisting
22:27
of what well there are three uh zeros in it and then there's a minus Alpha squared what's that
22:35
well that's like a 2 that's we're sort of representing Alpha squared but we have to put an anti 2 there because we have a minus one of them
22:46
okay so let's see if we can do this calculation um so there's there's quite a lot of terms here
22:54
there's three times times four so it'll be 12 things all together so what do we have to do in order to multiply these two things well we have to take all possible sums okay so zero plus
23:05
zero is zero so I'm going to do zero times only so I get zero zero zero two and I'm just adding
23:10
0 to all of these okay I have to do the same thing with this zero add zero to all of these
23:20
now I have to do the same thing with this one add one to all of these 1 plus 0 is 1 1 and 1 plus 2 Alpha so that's an interesting here so
23:30
we we need to calculate over here perhaps a different color so what is one plus two a
23:37
so 2A um so another way of thinking about that is it's one plus two plus anti zero right so
23:54
anti the anti of two okay one wave of saying what that is it's 2 plus anti zero so if we write it
24:03
this way and sort of we use distributivity we would get three plus anti-0 which is
24:13
anti-3 so according to that calculation we should have a three a there
24:23
and in terms of uh an actual um you know poly number what poly number is this okay so we get
24:33
uh six zero so that's six uh we have these three ones here so that's like three Alpha
24:40
and then we have these two uh two A's or anti-2s okay so that's like Alpha squared but with a minus
24:49
so minus two alpha squared and there's three a anti three corresponds to minus Alpha cubed
24:58
does that look like what we'd expect two times three uh three times Alpha
25:04
yes minus two alpha squared yes and minus Alpha cubed good
25:11
let's do another example say one minus Alpha cubed okay so that's going to be what well one minus
25:20
Alpha as an M set in the sort of more familiar way that's a zero representing the one and the
25:27
minus Alpha it's like a one but with a an a here okay anti anti one okay so times zero anti one
25:38
times 0 and T1 all right so we're going to get an M set consisting of all possible triple sums
25:48
element here element here element here adding them up okay so um so uh okay so there'll be
25:56
like a zero plus zero plus zero that'll be one and then there'll be a zero plus zero plus one
26:06
a okay and then there'll be a zero plus one a plus zero it'll be a zero plus one a plus one a
26:17
that's four of them and then with the 1A so one a plus zero plus zero one a plus
26:23
zero plus one a one a plus one a plus zero and one a plus one a plus one a
26:34
okay what are we gonna get when we do all this okay so the first thing here is zero plus zero
26:39
plus zero that's going to be zero what's this thing here zero plus one a so that's gonna be one a and in fact uh so is that and so is so is so is that so we're gonna get one a
26:50
and so is this one so it'll be one a one a one a so I dealt with this one here this one here
26:58
this one here and this one here okay what about this thing here zero plus one a plus one a well
27:06
what is 1A plus 1A anti one plus anti one well uh let's do a little sum over here
27:16
okay so anti 1 plus anti one okay well one way of thinking about what an anti one is it's one
27:24
plus anti zero so maybe we could write it like this okay that makes it clear that this is 2
27:30
plus anti zero plus anti-zero is zero so we're getting two so anti one plus anti one is two
27:42
it's the same kind of story with the parity there's there's an even number of antes and so we're getting something it doesn't involve aunties so this thing here is going to give us a two
27:54
as is this one and this one oh sorry not Plus just a single two and also
28:05
another two and another two and finally this last one here 31 plus 81 plus 81
28:13
same kind of story but we're getting a three with an ante
28:21
and if we wanted to write that out as a poly number let's squeeze it down here
28:29
maybe in blue so this is what this is one there's three of these one a so that's minus three Alpha both things there there's three of
28:39
these so plus three Alpha squared and there's one of these so minus a single Alpha cubed
28:49
so we've done a little binomial expansion in this mset world okay but now we're able to
Integral (Laurent) polynumbers
28:57
move in a different direction still staying in the world of poly numbers okay but we're going to use the fact that we have integers now in uh more subtle more expanding fashion
29:09
and this leads us to what we're going to call integral polynumbers or perhaps one could say Laurent poly numbers but I'm not going to actually use that notation I'm
29:17
going to prefer integral poly numbers so an integral poly number is an mset of integers
29:27
poly number we said before was an mset of natural numbers like zeros ones twos Etc
29:35
now an mset of integers
29:40
so for example here P here's an M set of
29:49
editors negative 2 negative one negative 1 negative one zero three three
29:55
and we can now interpret this in an algebraic fashion by being sort of consistent and thinking
30:06
of these negative sizes just representing powers of alpha which have negative numbers as exponents
30:14
so this two bar here is giving us an alpha to the minus two these things here these One bars
30:22
are alpha to the minus one there's three of them the single zero is a one and these two alpha cubed
30:28
these two threes give us two alpha cubed so in terms of a box here's a box that corresponds to
30:36
this so there's a box okay and it has a two bar in where's the two bar um well uh this thing here
30:47
is essentially the two bar because a two would look like a box a black box with two empty boxes
30:54
inside it if we want to negate that what we have to do is we have to take the the M side
30:59
which consists of the antes of all the ingredients so we have to take the antes of the two involved
31:05
here so this is the um what the the two bar looks like and similarly the One bars here that one that
31:11
one and that one represented by a black box with a red box inside the zero is just represented with
31:19
the single empty set and the threes well there's three and there's another three
31:26
now what in terms you know in terms of our familiar uh notation for for amsets if we
31:34
just look at the positive part of this maybe I should put it down a little bit
31:41
let me let me write it like this okay so we just looked at the the positive part there's a single oh one okay there's a zero Alphas zero Alpha squared and there's two alpha cubes so
31:54
that would be sort of the our usual poly number representation as a multiplicity list uh with
32:01
just positive powers of alpha but now we have also three Alpha to the minus ones and an alpha to the
32:08
minus two so we can represent that by essentially going in this other direction going up from this
32:13
this bar here okay so there's three here in this position and one here in this position
32:21
this is sort of the alpha to the zero position Alpha what to the one alpha to
32:26
the two alpha to the three this is Alpha to the minus one here's Alpha to the minus two
32:33
so this is sort of consistent with what we're doing previously but we're kind of going in a different direction so in my next video I'm going to have to say more about you know how
32:44
to think about these integral polynomials like what what do they mean how do we represent them or how do we think about them but let's just do a bit of arithmetic with them to give us an idea of
32:54
you know how this works okay so let's add two integral poly numbers here's an integral poly
Arithmetic with integral polynumbers
33:00
number one bar one bar two here's another one three bar one two four to add them we just make
33:06
a Big M set dump everything together so there's a one bar there's a one bar there's a two there's a
33:12
three bar there's a one there's a two there's a four okay okay so we could rewrite this maybe a
33:17
slightly more organized fashion like this one bar one bar uh one two two oh there's a three bars
33:23
one we could put maybe the three bar there okay three bar one bar one bar uh one two two and four
33:31
okay and in terms of you know interpretation in terms of poly numbers this would be here uh this
33:38
would be two alpha to the minus one plus Alpha squared okay that thing there and this thing
33:45
here would be an alpha to the minus three plus an alpha plus Alpha squared plus Alpha to the four
33:52
okay round bracket and what are we getting out of this we're getting um an alpha to the minus three
33:59
plus uh two alpha to the minus one plus Alpha plus two alpha squared plus Alpha to the four
34:10
does that sound reasonable yes I think it does
34:17
okay here's another example a little bit more sophisticated now because we're going to combine these two rolls of negative numbers in slightly different ways
34:28
okay now have a look at this thing here three bar one bar two ante
34:34
one bar anti zero two three first of all let me Express the meaning of this in more familiar
34:40
sort of poly number language what is this thing representing it's representing the poly number Alpha to the minus 3 plus Alpha to the minus one and without the ant here would be an alpha square
34:54
but there's an anti here so we have to think of it as being minus Alpha squared okay and what about
35:00
this one over here well the one bar anti so one bar is representing Alpha to the minus one but
35:07
we have a Nancy so it's minus Alpha to the minus one plus one plus Alpha squared plus Alpha cubed
35:16
okay and then when we uh put them all together well let's do it over here so we just dump
35:21
them all together three bar one bar two anti 1 bar anti zero two three okay and what is that
35:34
well now there's some cancellation that happens because in the same asset we're seeing some
35:40
objects and they're anti so there's a one bar here and there's an anti one bar they're going to cancel there's a a 2 and an anti-2 they're going to cancel the three bar and the three
35:50
they are not aunties they're not going to cancel they stay where they are so we're going to get a three bar what do we say these guys cancel these guys cancel we're going to get a zero and a three
36:01
so over here in on the polynomial side we should be getting Alpha to
36:07
the minus 3 plus 1 plus Alpha cubed that I suppose that's reasonable
36:15
okay so let's do a multiplication so two bar one times one bar one bar anti-3
36:24
okay so in terms of polynomials or poly numbers this would be this one here is like Alpha to the
36:32
minus two plus Alpha times 2 Alpha to the minus one plus three ante that's minus Alpha cubed
36:51
okay so at the level here what do we have to do we have to make a Big M set consisting of all possible sums of these things all possible sums okay so um two bar plus one bar what is that
37:05
well two bars the same as minus two uh one bar is the same as minus one when we
37:12
add them we're going to get minus three or three bar so we're going to get a three bar
37:18
that's that's sum this sum is another three bar we get two bar plus three anti let's think about that
37:25
um maybe I could do that over here so 2 bar plus three anti so the three ante you can think of as
37:36
three plus and t zero okay when we do it that way the two bar plus the
37:43
3 will give us a one so we get one plus anti-zero which is one anti
37:52
so uh which one was that that was this two bar plus three anti again sort of an odd number of
38:01
anti's gives us an anti but otherwise it's like two bar plus three so it's like one so we're
38:09
getting um one ante so we've done um three sums so far okay so we have uh still one plus one bar
38:19
well that's zero one plus one bar that's zero and one plus three
38:26
anti that's the same story as that the one plus three is four so we can get four ante
38:35
so what is this telling us we should be getting uh two alpha to the minus three it's that a one
38:44
plus plus two plus two a one ante so that's minus Alpha and a four anti so minus Alpha to the four
38:55
does that correspond to what we would expect two alpha to the minus three
39:02
um minus Alpha yeah two yes minus Alpha fourth I think that's that's right
39:14
so it seems as if we have an interesting arithmetic but now we've we've used these
39:20
negative numbers to enlarge our arithmetic or algebra of with polynomials or polynumbers in
39:26
in in in two ways not just in terms of adding negative coefficients the possibility of that
39:32
but also in terms of adding the possibility of negative exponents and this is a a departure from
39:40
the usual story of polynomials okay and I'm going to talk more about that in my my next video how
39:47
to think about that we're going to see some some sort of new insights into you know what the world
39:54
of polynomials and their algebra really looks like I'm Norman Wildberger thanks for listening [Music]