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Classical to Quantum | Relativistic velocity addition (simplified) | Wild Egg Maths

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In 1905 Einstein introduced his Special Theory of Relativity (SR), with many unintuitive consequences. One of these is that when we consider "compositions" of relative motions, then the relative velocities are related in a different way than in Newtonian mechanics. In this video we use our simplified framework for SR to see that this law is just a simple consequence of algebraic relations between quantities associated to complex numbers. But we do not use the ordinary theory of complex numbers; rather the relativistic version that we call red complex numbers. This is an algebraic arena which is valuable for physicists understanding not just of SR, but also quantum mechanics. This video is part of the Classical to Quantum playlist for Members of the channel. Please consider joining and accessing dozens of specially created videos on a wide range of intermediate to advanced topics. The full playlist is at • Introduction to QM and the two slit e...

Transcript

0:00

hello everyone thanks for joining me on

0:02

this adventure from classical to Quantum

0:04

and right now we're talking about

0:06

special relativity in

0:09

particular relativistic velocity

0:11

addition in a simplified fashion which

0:15

connects very closely to just simple

0:20

algebraic manipulations essentially with

0:22

complex numbers although they are the

0:24

red complex numbers not the traditional

0:27

blue

0:28

ones okay so to motivate the story we're

0:31

in a onedimensional space and we'll

0:32

actually consider the same situation

0:33

that we looked at last time okay where

0:36

we have an observer a which is

0:38

stationary from our external point of

0:40

view just to simplify things we have

0:42

another Observer B which is moving with

0:45

velocity V equals 1/2 according to

0:48

a so A and B are what we call autochron

0:53

observers they happen to meet at time T

0:56

equals z okay where which will be there

0:59

because a stationary and there's a third

1:02

Observer uh last time it was a particle

1:04

but this time it's just an observer

1:06

called C who's moving in this Direction

1:08

with velocity minus one4 also with

1:10

respect to a and it's also autoc

1:13

chronous so it will also meet A and B

1:16

exactly there at time T equals z for a

1:20

so these autoc chronous observers each

1:22

one of them establishes sort of

1:24

canonical way of of

1:28

coordinatization

1:31

clock ticking one that's the point C and

1:34

then a conjugate Point C star which

1:37

depends on the uh the signals that we're

1:40

that we're using either light signals or

1:42

sound signals it doesn't really matter

1:44

which okay

1:46

so in a time space the situation could

1:49

be regarded this way if we want to put a

1:52

stationary so it has a

1:54

Vertical World line for us then here are

1:58

the relative IC signal lines okay that

2:02

represent the world lines of sound or

2:06

light emanating to the right or to the

2:08

left in this onedimensional space we

2:11

have time axis we have an x- axis and

2:12

this is with respect to a and the other

2:15

coordinate that for a that's relevant is

2:17

this one here there well all right good

2:21

now in terms of coordinates okay the

2:26

coordinate of a with respect to a is

2:27

obviously one the coordinate of B with

2:30

respect to a is 1 + 12

2:34

J B's World line is here B is

2:37

represented by this point this point has

2:39

coordinates 1 and 1/2 so it's

2:41

represented by the red complex number 1

2:44

12

2:46

J C sub a the coordinate of C with

2:49

respect to a so here is C's World line

2:52

representing this Observer which is

2:55

moving to the left so the war line

2:58

sloping this direction passing through

2:59

the Point 1 - 1/4 so its coordinate is 1

3:04

-4

3:06

J and now what's the velocity how do we

3:09

introduce the Velocity in terms of these

3:11

coordinates well the

3:13

velocity of B with respect to a so we're

3:16

using the same kind of notation with the

3:19

subscript here is with respect to that

3:21

Observer velocity of B with respect to a

3:24

is equal to how do you get that well you

3:26

look at B sub a it has has a t

3:30

coordinate it has an x coordinate those

3:32

represent the the displacements in time

3:36

and space as we go from the the origin

3:38

which is the point 0 0 in A's coordinate

3:41

to the point B which is

3:43

one2 so we have to go up one and across

3:47

1/2 so the delta T is 1 the Delta X is

3:51

1/2 so velocity is Delta X over delta T

3:55

right so we're just going to do exactly

3:57

that so the 1/2 is the Delta X the one

4:00

is the delta T so we'll just take the

4:02

ratio2 / 1 which is a

4:05

half which agrees with what we

4:08

originally say that the velocity of B is

4:10

indeed 1/2 and the velocity of C with

4:13

respect to a well we look at this

4:15

complex number we take the J coefficient

4:19

put that in the numerator that's minus a

4:20

quarter that's the Delta X as we go from

4:24

here to here Delta X changes by minus A4

4:28

and we divide by the delta T T which is

4:30

1 to get minus 1/4 which again agrees

4:32

with our our setup so this is how we're

4:34

going to introduce velocities in this

4:37

situation just in the same way we always

4:40

introduce velocities a Delta X over a

4:42

delta T in whatever coordinate system

4:44

you're working with so a natural

4:47

question then is well what about the

4:49

relationship between B and C if B is

4:52

looking at C what is the velocity of C

4:56

with respect to

4:58

B now you might say well B is going in

5:01

this Direction with speed of a half C is

5:03

going in this direction the speed of a

5:05

quarter you know classically you would

5:08

add those two velocities and say oh the

5:10

speed of C with respect to B should be

5:12

minus

5:14

3/4 but we'll see that that's not the

5:16

way the relativistic world works okay so

5:19

our aim is to find V subb of C in other

5:22

words the velocity of C with respect to

5:24

b or reciprocally V Sub C of B the

5:27

velocity of B with respect to C so what

5:29

we already know we know that b sub a is

5:32

this so a subb will be the inverse of

5:34

that in the world of red complex numbers

5:36

so we take the inverse of that we've

5:38

already seen that's 4/3 minus 2/3 J so

5:41

from that we can deduce that the

5:43

velocity of a with respect to B is this

5:46

quantity that we look at we take

5:48

the X component minus 2/3 divide by the

5:53

T component that's 4/3 we get minus

5:58

1/2 okay okay that's not

6:02

surprising and a sub c is C sub a

6:07

inverse so we have to take the inverse

6:08

of this so we complex conjugate up there

6:12

and the quadrants 1^ 2 - 1/4 s we get 15

6:17

over 16 in the denominator we take the

6:19

reciprocal we get 16 over 15 * 1 and 16

6:23

over 15 * 1/4 is 4 over 15 *

6:28

J

6:31

all right so the velocity of a with

6:35

respect to C because this is a sub c so

6:38

we take 4 15 / by

6:43

1516 that's the same as 4 over 16 or

6:46

one4 so we just make the observations

6:49

that V subb of a is minus V sub a of B

6:53

and similarly V Sub C of a is minus V

6:56

sub a of C so now what we're interested

6:59

in say to calculate something like this

7:00

is to find C subb and we know how to do

7:03

that because of this basic

7:04

multiplicative relationship between the

7:07

coordinates of the various observers

7:10

with respect to each other C subb is

7:12

equal to C sub a * a sub B and it's easy

7:15

sort to remember because it's almost a

7:17

cancellation of the A's okay it's almost

7:20

like what's called Einstein notation um

7:24

in in physics we have a lower index and

7:26

a and an upper index you have to sum

7:28

over them they the kind of disappear so

7:30

what's left is just a a c subb okay so C

7:33

sub a we've just found uh we actually

7:35

know that that's 1 - one4 J and the a

7:38

sub B that's what we found up here

7:40

that's 4/3 - 2/3 J so we make that

7:42

multiplication and we get 3 minus J and

7:45

that tells us that V subb of C

7:48

is the X coefficient which is minus1

7:52

ided by the T coefficient which is three

7:54

has to get - 2/3 and we note that this

7:57

is not Theus 3/4 that we might have

8:01

suspected naively if we were just doing

8:03

sort of classical

8:05

mechanics adding velocities in the kind

8:08

of obvious way so let's be a little bit

8:10

more formal just to set things up if a

8:13

and b are autoc chronous

8:15

observers with B sub a equal little a

8:19

plus little B J then the velocity of B

8:23

with respect to a is by definition so V

8:25

Suba of B it's

8:28

the coordinate

8:30

x / the coordinate T So B A and of

8:34

course this is undefined if a equals z

8:37

and we're not going to always specify

8:40

that that's just obvious if we have a

8:41

denominator in our our formula the

8:44

formula is just uh you know put on a

8:45

shelf it's it's not valid okay so we

8:47

don't worry about

8:49

that okay so an initial Lema let's just

8:52

check this observation that we made

8:53

before that V subb of a is minus V Suba

8:57

of B in general so suppose B sub a is a

9:01

plus BJ as before so that the velocity

9:03

here as we've defined is B over a well

9:05

then a subb is the inverse of this in

9:07

the red complex number so we take the

9:09

complex conjugate a minus B J and we

9:11

divide by the quadrants which is a^ 2

9:13

minus b^ 2 so we get in terms of a t

9:16

coordinate a over a 2 - b^ 2 minus B

9:20

over A2 - b^ s there's the x coordinate

9:24

times J okay so how do we calculate the

9:27

velocity of a with respect to B we take

9:30

this x coordinate which is minus B over

9:34

A2 minus b2 and we divide by the T

9:37

coordinate which is a over a 2 - b^ 2

9:40

and the a^ S - B s's cancel so we just

9:43

have minus B over a which is the same as

9:46

minus minus V sub a of B and here is the

9:51

main result of our lecture a formula

9:53

found essentially by Einstein and it's

9:56

the relativistic velocity addition

9:58

formula says if a B and C are autoc

10:01

chronous observers so they all

10:02

conveniently are passing through the

10:04

same point at time T equals z and they

10:08

set up their coordinates in the uh in

10:11

the standard way using um The Tick of

10:15

their clock at one and the corresponding

10:18

conjugate Point okay so if a b c are

10:21

autoc chronous observers then the

10:24

velocity of C with respect to a is

10:28

velocity of B with respect to to a plus

10:29

the velocity of C with respect to B

10:32

divided by 1 plus the product of these

10:35

two things V sub a b v sub BC so if

10:38

there was no denominator here it was

10:40

just a one then we would get the sort of

10:42

classical gas as to how velocities add

10:46

okay so it's just a little bit of

10:47

algebra suppose B sub a is a plus BJ and

10:51

C subb is C plus d j so that means that

10:54

c sub a which is C subb time B sub a as

10:58

it always is is a plus b

11:02

j that's the B sub a times C plus DJ

11:06

that's the C sub B and when we multiply

11:08

those in the world of red complex

11:10

numbers we get AC plus b d because of

11:12

course j2 equal 1 and we get a d plus b

11:16

c j okay so this quantity here that

11:19

we're talking about V sub a B plus v sub

11:22

b c over 1 plus v sub a b v sub B C

11:25

equals what well the V sub a b we know

11:28

what that is that's B over a the V sub b

11:33

c we know what that is it's D over C so

11:37

we have to add those and in the

11:40

denominator we have to put one plus the

11:41

product

11:42

b/ a * D over C and now we simplify this

11:47

in the obvious way we multiply through

11:49

top and bottom by a * C when we do that

11:53

we get a B * C up here plus an a * D

11:57

alog together in the numerator and in

11:59

the denominator we just get a C+ b d and

12:03

that's exactly V sub a of C because here

12:07

is C sub a okay there it is there so

12:11

this expression is the X component which

12:14

is the coefficient of j a d plus BC

12:17

that's appearing here in the numerator

12:19

over the T component which is AC plus BD

12:22

that's appearing in the denominator

12:26

there and uh yeah so in principle this

12:29

could be very familiar to you because

12:31

you could have learned the same theorem

12:33

in ordinary complex number story okay

12:36

where the the story is it really

12:39

discussing slopes you would you would

12:40

interpret it in terms of slopes you know

12:43

how do how do slopes of of complex

12:45

numbers relate when they're when you

12:48

multiply them okay and it's maybe

12:50

instructive to just go through the same

12:52

exact story with ordinary complex

12:54

numbers and just a minus sign crucially

12:56

that appears okay but it's algebraically

13:00

very simple and in fact sort of elegant

13:02

and you sort of see that I mean is it

13:06

physics or is it mathematics that we're

13:08

seeing here that's an interesting

13:10

question I mean is is this some some

13:11

deep property of of of the physical

13:14

world or is it just an elementary

13:17

property of mathematics which just

13:19

happens to be manifesting itself in the

13:21

physical

13:22

world that's an interesting question

13:25

that um we'll be coming back over and

13:27

over again on our our journey uh towards

13:29

quantum mechanics so this little

13:31

expression here is quite tidy and it

13:33

deserves perhaps its own name so we're

13:36

going to call it V sub one with this

13:39

sort of U plus sign V sub2 and we're

13:43

going to call this the hyperbola sum

13:45

it's like a sum but it's not an ordinary

13:47

sum it's a hyperbola

13:49

sum that's sort of analogous to what in

13:52

other places I call Circle sum okay so

13:55

let's do some examples

13:58

1/2 plus 1/2 1/2 hyperbola sum 1/2 is

14:03

well you have to take the sum ordinary

14:05

sum on the the top that's um2 + 1/2

14:08

that's one and in the denominator you

14:11

have 1 plus the product so 1 plus a

14:13

quarter which is alog together 5

14:15

quarters you take the reciprocal you get

14:16

four fifths how about one hyperbola sum

14:19

one well we get 1 plus 1 on the top and

14:21

we get 1 + 1 in the bottom so we get one

14:26

how about 1/2 hyperbola sum to now you

14:30

might say wait a minute Norman this

14:32

corresponds to something that's going

14:34

faster than our

14:37

signal whether it be light or um or

14:40

sound yeah so doesn't bother us does it

14:44

there's nothing in the theory that we've

14:46

developed so far that restricts us to

14:48

just what's usually called the upper

14:50

light cone like just mathematics

14:53

mathematics works everywhere now you

14:55

might say well the physics doesn't well

14:56

that's that's a question right that's

14:58

not something that's so easily

14:59

established you can claim that but

15:02

actually to to check whether it's true

15:04

or not is a far different story okay

15:06

physicists have not checked whether

15:08

that's true okay so the idea that

15:10

nothing can go faster than the speed of

15:13

light is not something that we are going

15:14

to incorporate just as a matter of

15:16

principle okay it's something that may

15:18

be true and may not be true and part of

15:22

what we're interested in is you know

15:23

investigating things in such a a good

15:25

way that maybe the truth or otherwise of

15:28

such a statement becomes more clear but

15:30

initially at least we're going to be

15:32

open-minded so this is a totally

15:34

legitimate thing to take a hyperbola sum

15:36

of so if we add 1/2 plus two in the

15:39

ordinary way we get U two and a half

15:41

which or five halves if we take one plus

15:44

the product the product is

15:46

one uh so we get 1+ 1 is two so we have

15:49

five halves over two so we get five

15:53

quarter

15:55

another speed you might say that's

15:57

bigger than one how about 1/3 hyperbola

16:00

sum - 1/5 well there it is there 1/3 -

16:03

1/5 over 1 - 115 that's 17th and say

16:07

three hyperbola sum minus three well

16:10

that's obviously zero because you get

16:11

zero in the

16:14

numerator okay an important theoretical

16:17

uh thing about this thing it's probably

16:19

important enough I should put this in a

16:21

box okay it's like an associative law

16:24

for this operation of hyperbola sum okay

16:27

that V1 hyperbola sum V2 hyperbola sum

16:31

V3 equals V1 hyperbola sum V2 hyperbola

16:34

sum

16:35

V3 okay and so you do this exercise and

16:38

show in fact that what you end up

16:40

getting is some kind of variant of this

16:42

where we have V1 plus V2 plus V3 because

16:45

there's three of them and then we have a

16:47

cubic term V1 V2 V3 and in the

16:50

denominator we have a 1 plus well

16:52

there's more than one quadratic term

16:54

there's V1 V2 plus V2 V3 plus V1 V3

16:59

that's quite elegant so the way you

17:02

might want to think about this is

17:03

there's a constant term here there's

17:05

some linear term here which is very

17:08

symmetrical Elementary and symmetrical

17:11

there's a quadratic term here which is

17:13

also sort of Elementry and symmetrical

17:16

and there's a cubic term up

17:19

here so maybe that's a clue to this

17:22

other one generalize this so what would

17:24

happen if we had four velocities and we

17:27

took hyperbola sums of all four

17:29

V1 V2 V3 and V4 what would we get so

17:33

maybe I haven't made it explicit um but

17:36

I've I've said it in directly in a

17:37

number of times that if we consider one

17:40

of these autoc chronous observers whose

17:43

coordinate system is set up the way I've

17:45

I've suggested that we we start with the

17:48

the red signal lines whatever they are

17:51

okay and we have some point representing

17:54

some Observer on the world line then

17:56

we're going to take its conjugate with

17:58

respect to to these two things and

17:59

that's essentially a harmonic conjugate

18:03

and that's essentially some kind of

18:05

reflection in U one of them with respect

18:08

to the other one so with that kind of

18:10

coordinate system then if you ask what's

18:12

the velocity of the the signals

18:14

themselves the answers are always either

18:16

minus one or plus one depending on which

18:18

one you ask okay so that's a um thing

18:21

that automatically happens for all of

18:23

these observers all of these observers

18:24

are going to say if you you ask what's

18:26

the velocity of this thing going this

18:27

way they'll say oh it's minus one and

18:29

what's the velocity of the signal going

18:30

in that direction it's always plus one

18:33

so having said that let's look at some

18:34

inequalities that are quite interesting

18:37

so the first one is if we take two

18:40

numbers A and B and they're between zero

18:42

and one and strictly less than one but

18:45

they're positive okay then the claim is

18:48

that their hyperbola sum will also be in

18:51

exactly the same range it will be

18:53

somewhere between zero possibly zero up

18:56

to one but not being equal to one

18:59

okay so proof If a and b are between Zer

19:03

and one in this fashion then a plus b

19:07

over 1 plus a the hyperbola sum this

19:09

thing here is obviously bigger than

19:10

equal to zero because well A and B are

19:13

bigger than equal to zero and this thing

19:15

here is also bigger than or equal to

19:16

zero so it's uh it's obviously positive

19:19

and what about the other inequality how

19:21

do we know that this thing is less than

19:23

one well this inequality is equivalent

19:25

to the following because if a and b are

19:28

positive then this quantity in the

19:30

denominator is positive so this

19:32

inequality can be restated by

19:34

multiplying through by the positive

19:37

denominator here giving us a plus b is

19:39

less than 1 + a so these two things are

19:42

equivalent under

19:45

this condition now this thing here then

19:48

can be Rewritten by bringing everything

19:50

to the right hand side so we get zero is

19:52

less than well 1 + a B minus a minus B

19:55

and that's just what you get when you

19:57

expand 1 - A * 1 - B so now if a and b

20:04

are less than one and both positive well

20:06

each of these numbers here okay is going

20:10

to be uh strictly

20:13

positive strictly

20:16

positive and so their product is going

20:18

to be strictly positive and these things

20:20

are all in equivalent so this being true

20:23

means that this thing's true means that

20:25

this part of inequality is true okay so

20:27

this has an important

20:29

uh consequence so this is going to end

20:32

up being important for us right

20:34

physically what this means is that you

20:36

know if if one of these observers is

20:37

like a train okay so a is stationary and

20:41

B is like a train okay and then on this

20:43

train B shoots uh a bullet you know

20:46

forward okay so usually as we've seen

20:49

the velocities add that's the way we

20:51

would think about things but in this

20:53

context the velocities don't add they

20:55

they have this hyperbolic sum okay but

20:57

the point is that

20:59

if the train and the bullet are both

21:01

going slower than our signal speed then

21:05

the

21:06

resulting the resulting combination of

21:09

these two things will also be slower

21:11

than the signal speed and that's true

21:14

not just when the signal speed is light

21:17

it's also true when the signal is

21:22

sound it's also true when the signal is

21:25

sound so that same phenomena is

21:28

happening it's just the mathematics of

21:30

it and what happens when we consider

21:32

because we've said well maybe we can

21:34

consider things moving faster than our

21:36

signal speed why not mathematically it's

21:39

it's possible so let's just uh do a

21:41

little computation here what would be

21:43

two hyperbola sum three so this would be

21:48

sum of a train going faster than our

21:50

signal and the bullets going even more

21:53

faster than the signal and what's the

21:54

combination of of these two things okay

21:57

well uh we use the same formula right

21:59

it's 2 + 3 over 1 plus the product

22:02

product is

22:04

six so that's five over

22:10

7 that's less than

22:12

one that's less than

22:15

one that's a kind of curious thing okay

22:18

so we might have to ponder uh the

22:21

significance of that but more generally

22:23

show that if you have numbers A and B

22:25

which are bigger than one then also the

22:28

hyperbola sum of them is positive but

22:31

less than one so generalizing this so

22:34

we're coming into contact now with some

22:37

interesting sort of aspects of special

22:39

relativity and I want to emphasize to

22:41

you that this is not uh not a feature of

22:45

light predominantly okay it's that's not

22:47

really the the thing it's it's just

22:49

having some signal propagation that has

22:52

certain properties uh particularly this

22:54

sort of parallel um postulate property

22:57

which is really

22:59

um you know in the context of an apine

23:01

geometry for our time space okay but in

23:05

particular uh a lot of things that we

23:07

maybe formerly thought were really

23:09

special things having to do with the

23:11

their amazing special role of light in

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special relativity maybe that's not

23:16

really the case maybe these phenomena

23:18

are much wider and and more um more

23:22

General kinds of things that happen in

23:24

uh perhaps even very slow moving

23:27

situations

23:29

is

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